Let's explore your resume and then dive into a coding question.
First, regarding your resume:
Now, for the coding question:
Given a list of integers, write a function to find the contiguous sub-array with the largest sum. For example, if the input is [-2, 1, -3, 4, -1, 2, 1, -5, 4]
, the output should be [4, -1, 2, 1]
, with a sum of 6. Explain your approach, and provide a working implementation of the function in your preferred programming language. Consider edge cases such as an empty input list or a list with only negative numbers. What is the time complexity of your solution? Can you optimize it further?
Okay, let's explore your resume and then dive into a coding question.
First, regarding your resume:
Now, for the coding question:
Given a list of integers, write a function to find the contiguous sub-array with the largest sum. For example, if the input is [-2, 1, -3, 4, -1, 2, 1, -5, 4]
, the output should be [4, -1, 2, 1]
, with a sum of 6. Explain your approach, and provide a working implementation of the function in your preferred programming language. Consider edge cases such as an empty input list or a list with only negative numbers. What is the time complexity of your solution? Can you optimize it further?
The problem requires us to find a contiguous subarray with the maximum sum within a given array. A brute-force approach would be to consider all possible subarrays, calculate their sums, and then return the subarray with the largest sum. However, this approach is inefficient.
A more efficient approach is Kadane's Algorithm, which uses dynamic programming to solve this problem in linear time. The algorithm maintains two variables: max_so_far
and current_max
. max_so_far
stores the maximum sum found so far, and current_max
stores the maximum sum ending at the current position. The algorithm iterates through the array, updating current_max
at each step. If current_max
becomes negative, it's reset to 0. max_so_far
is updated with the maximum of max_so_far
and current_max
at each step.
To track the subarray, we maintain start_index
and end_index
to keep track of the start and end of the maximum sum subarray. When current_max
becomes negative, we update the start_index
to the next element.
def max_subarray(nums):
"""Finds the contiguous subarray with the largest sum."""
max_so_far = float('-inf')
current_max = 0
start_index = 0
end_index = 0
j = 0
for i in range(len(nums)):
current_max += nums[i]
if current_max > max_so_far:
max_so_far = current_max
start_index = j
end_index = i
if current_max < 0:
current_max = 0
j = i + 1
return nums[start_index:end_index + 1]
# Example usage
nums = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
result = max_subarray(nums)
print(f"The maximum subarray is: {result}") # Output: [4, -1, 2, 1]
print(f"The sum is: {sum(result)}") # Output: 6
Kadane's Algorithm has a time complexity of O(n), where n is the number of elements in the input array. This is because the algorithm iterates through the array only once.
Kadane's Algorithm has a space complexity of O(1), which means it uses a constant amount of extra space, regardless of the size of the input array. The algorithm only uses a few variables to store intermediate values, such as max_so_far
, current_max
, start_index
, and end_index
.
max_so_far
is initialized to negative infinity, ensuring that even the largest negative number is selected.Here's the code to handle the edge case where input list is empty:
def max_subarray(nums):
"""Finds the contiguous subarray with the largest sum."""
if not nums:
return []
max_so_far = float('-inf')
current_max = 0
start_index = 0
end_index = 0
j = 0
for i in range(len(nums)):
current_max += nums[i]
if current_max > max_so_far:
max_so_far = current_max
start_index = j
end_index = i
if current_max < 0:
current_max = 0
j = i + 1
return nums[start_index:end_index + 1]